# Example 12 - Chapter 8 Class 12 Application of Integrals (Term 2)

Last updated at May 29, 2018 by Teachoo

Last updated at May 29, 2018 by Teachoo

Transcript

Example 12 Find the area of region bounded by the line =3 +2, the and the ordinates = 1 and =1 First Plotting =3 +2 In graph Area Required = Area ACB + Area ADE Area ACB Area ACB = 1 2 3 equation of line Area ACB = 1 2 3 3 +2 Since Area ACB is below x-axis, it will come negative , Hence, we take modulus Area ACB = 1 2 3 3 +2 = 3 2 2 +2 1 2 3 = 3 2 2 3 2 +2 2 3 3 2 1 2 +2( 1) = 3 2 4 9 4 3 3 2 2 = 2 3 1 2 = 2 3 + 1 2 = 1 6 = 1 6 Area ADE Area ADE = 2 3 1 y equation of line = 2 3 1 3 +2 = 3 2 2 +2 2 3 1 = 3 (1) 2 2 +2 1 3 2 2 3 2 +2 2 3 = 3 2 +2 2 3 4 3 = 7 2 + 2 3 = 25 6 Thus, Required Area = Area ACB + Area ADE = 1 6 + 25 6 = 26 6 = 13 3

Examples

Example 1

Example 2 Important

Example 3

Example 4

Example 5 Important

Example 6 Important Deleted for CBSE Board 2022 Exams

Example 7 Important Deleted for CBSE Board 2022 Exams

Example 8 Important Deleted for CBSE Board 2022 Exams

Example 9 Deleted for CBSE Board 2022 Exams

Example 10 Important Deleted for CBSE Board 2022 Exams

Example 11

Example 12 You are here

Example 13 Important

Example 14 Important Deleted for CBSE Board 2022 Exams

Example 15 Important

Chapter 8 Class 12 Application of Integrals (Term 2)

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About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.